Identify the equation of the circle with center at (2, -3) and radius 4:
$$(x - 2)^2 + (y + 3)^2 = 16$$
$$(x - 2)^2 + (y + 3)^2 = 8$$
$$(x + 2)^2 + (y + 3)^2 = 8$$
$$(x + 2)^2 + (y - 3)^2 = 16$$

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